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Two policemen, $\mathrm{A}$ and $\mathrm{B}$, fire once each at the same time at an escaping convict. The probability that A hits the convict is three times the probability that B hits the convict. If the probability of the convict not getting injured is $0.5,$ the probability that $\mathrm{B}$ hits the convict is
(A) 0.14
(B) 0.22
(C) 0.33
(D) 0.40


Question ID - 156266 | Toppr Answer

Two policemen, $\mathrm{A}$ and $\mathrm{B}$, fire once each at the same time at an escaping convict. The probability that A hits the convict is three times the probability that B hits the convict. If the probability of the convict not getting injured is $0.5,$ the probability that $\mathrm{B}$ hits the convict is
(A) 0.14
(B) 0.22
(C) 0.33
(D) 0.40

1 Answer - 5876 Votes

3537

Answer Key : (A) -

(A) 0.14



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