# Two plates are connected by fillet welds of size $10 \mathrm{~mm}$ and subjected to tension, as shown in the figure. The thickness of each plate is $12 \mathrm{~mm}$. The yield stress and the ultimate tensile stress of steel are $250 \mathrm{MPa}$ and $410 \mathrm{MPa}$, respectively. The welding is done in the workshop $\left(\gamma_{m v}=1.25\right)$. As per the Limit State Method of IS 800: 2007 , the minimum length (rounded off to the nearest higher multiple of $5 \mathrm{~mm}$ ) of each weld to transmit a force $P$ equal to $270 \mathrm{kN}$ (factored) is (A) $90 \mathrm{~mm}$ (B) $105 \mathrm{~mm}$ (C) $110 \mathrm{~mm}$ (D) $115 \mathrm{~mm}$

## Question ID - 156318 | SaraNextGen Top Answer Two plates are connected by fillet welds of size $10 \mathrm{~mm}$ and subjected to tension, as shown in the figure. The thickness of each plate is $12 \mathrm{~mm}$. The yield stress and the ultimate tensile stress of steel are $250 \mathrm{MPa}$ and $410 \mathrm{MPa}$, respectively. The welding is done in the workshop $\left(\gamma_{m v}=1.25\right)$. As per the Limit State Method of IS 800: 2007 , the minimum length (rounded off to the nearest higher multiple of $5 \mathrm{~mm}$ ) of each weld to transmit a force $P$ equal to $270 \mathrm{kN}$ (factored) is (A) $90 \mathrm{~mm}$ (B) $105 \mathrm{~mm}$ (C) $110 \mathrm{~mm}$ (D) $115 \mathrm{~mm}$

$105 \mathrm{~mm}$