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In a relay race there are five teams $\mathrm{A}, \mathrm{B}, \mathrm{C}, \mathrm{D}$ and $\mathrm{E}$. Assuming that each team has an equal chance of securing any position (first, second, third, fourth or fifth) in the race, the probability that $\mathrm{A}, \mathrm{B}$ and $\mathrm{C}$ finish first, second and third, respectively is
(A) $\frac{1}{60}$
(B) $\frac{1}{20}$
(C) $\frac{1}{10}$
(D) $\frac{3}{10}$



Question ID - 156394 | SaraNextGen Top Answer

In a relay race there are five teams $\mathrm{A}, \mathrm{B}, \mathrm{C}, \mathrm{D}$ and $\mathrm{E}$. Assuming that each team has an equal chance of securing any position (first, second, third, fourth or fifth) in the race, the probability that $\mathrm{A}, \mathrm{B}$ and $\mathrm{C}$ finish first, second and third, respectively is
(A) $\frac{1}{60}$
(B) $\frac{1}{20}$
(C) $\frac{1}{10}$
(D) $\frac{3}{10}$

1 Answer
127 votes
Answer Key / Explanation : (A) -

(A) $\frac{1}{60}$

127 votes


127