The chainage of the intersection point of two straights is $1585.60 \mathrm{~m}$ and the angle of intersection is $140^{\circ}$. If the radius of a circular curve is $600.00 \mathrm{~m}$, the tangent distance (in $\mathrm{m}$ ) and length of the curve (in m), respectively are
(A) 418.88 and 1466.08
(B) 218.38 and 1648.49
(C) 218.38 and 418.88
(D) 418.88 and 218.38

Question ID - 156477 :-

The chainage of the intersection point of two straights is $1585.60 \mathrm{~m}$ and the angle of intersection is $140^{\circ}$. If the radius of a circular curve is $600.00 \mathrm{~m}$, the tangent distance (in $\mathrm{m}$ ) and length of the curve (in m), respectively are
(A) 418.88 and 1466.08
(B) 218.38 and 1648.49
(C) 218.38 and 418.88
(D) 418.88 and 218.38

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