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The Laplace transform $F(s)$ of the exponential function, $f(t)=e^{a t}$ when $t \geq 0,$ where $a$ is a constant and $(s-a)>0,$ is
(A) $\frac{1}{s+a}$
(B) $\frac{1}{s-a}$
(C) $\frac{1}{a-s}$
(D) $\infty$


Question ID - 156660 | Toppr Answer

The Laplace transform $F(s)$ of the exponential function, $f(t)=e^{a t}$ when $t \geq 0,$ where $a$ is a constant and $(s-a)>0,$ is
(A) $\frac{1}{s+a}$
(B) $\frac{1}{s-a}$
(C) $\frac{1}{a-s}$
(D) $\infty$

1 Answer - 5876 Votes

3537

Answer Key : (B) -

$\frac{1}{s-a}$



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