The Laplace transform $F(s)$ of the exponential function, $f(t)=e^{a t}$ when $t \geq 0,$ where $a$ is a constant and $(s-a)>0,$ is
(A) $\frac{1}{s+a}$
(B) $\frac{1}{s-a}$
(C) $\frac{1}{a-s}$
(D) $\infty$

Question ID - 156660 | SaraNextGen Top Answer

The Laplace transform $F(s)$ of the exponential function, $f(t)=e^{a t}$ when $t \geq 0,$ where $a$ is a constant and $(s-a)>0,$ is
(A) $\frac{1}{s+a}$
(B) $\frac{1}{s-a}$
(C) $\frac{1}{a-s}$
(D) $\infty$