The divergence of the vector field $\boldsymbol{V}=x^{2} \boldsymbol{i}+2 y^{3} \boldsymbol{j}+z^{4} \boldsymbol{k}$ at $x=1, y=2, z=3$
is

Question ID - 156707 | SaraNextGen Top Answer

The divergence of the vector field $\boldsymbol{V}=x^{2} \boldsymbol{i}+2 y^{3} \boldsymbol{j}+z^{4} \boldsymbol{k}$ at $x=1, y=2, z=3$
is