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The divergence of the vector field $\boldsymbol{V}=x^{2} \boldsymbol{i}+2 y^{3} \boldsymbol{j}+z^{4} \boldsymbol{k}$ at $x=1, y=2, z=3$
is


Question ID - 156707 | Toppr Answer

The divergence of the vector field $\boldsymbol{V}=x^{2} \boldsymbol{i}+2 y^{3} \boldsymbol{j}+z^{4} \boldsymbol{k}$ at $x=1, y=2, z=3$
is

1 Answer - 5876 Votes

3537

Answer Key : (133.9-134.1) -

133.9-134.1



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