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There are 4 women $\mathrm{P}, \mathrm{Q}, \mathrm{R}, \mathrm{S},$ and 5 men $\mathrm{V}, \mathrm{W}, \mathrm{X}, \mathrm{Y}, \mathrm{Z}$ in a group. We are required to form pairs each consisting of one woman and one man. $\mathrm{P}$ is not to be paired with $\mathrm{Z}$, and $\mathrm{Y}$ must necessarily be paired with someone. In how many ways can 4 such pairs be formed?
(A) 74
(B) 76
(C) 78
(D) 80


Question ID - 156786 | Toppr Answer

There are 4 women $\mathrm{P}, \mathrm{Q}, \mathrm{R}, \mathrm{S},$ and 5 men $\mathrm{V}, \mathrm{W}, \mathrm{X}, \mathrm{Y}, \mathrm{Z}$ in a group. We are required to form pairs each consisting of one woman and one man. $\mathrm{P}$ is not to be paired with $\mathrm{Z}$, and $\mathrm{Y}$ must necessarily be paired with someone. In how many ways can 4 such pairs be formed?
(A) 74
(B) 76
(C) 78
(D) 80

1 Answer - 5876 Votes

3537

Answer Key : (C) -

(C) 78



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