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The value of the integral, $I=\int_{2}^{4} \frac{x^{2}+1}{x^{2}-1} d x$ is______________


Question ID - 156901 | SaraNextGen Top Answer

The value of the integral, $I=\int_{2}^{4} \frac{x^{2}+1}{x^{2}-1} d x$ is______________

1 Answer
127 votes
Answer Key / Explanation : (2.2: 2.3) -

2.2: 2.3

127 votes

127
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