Which one of the following is correct?
(A) $\lim _{x \rightarrow 0}\left(\frac{\sin 4 x}{\sin 2 x}\right)=2$ and $\quad \lim _{x \rightarrow 0}\left(\frac{\tan x}{x}\right)=1$
(B) $\lim _{x \rightarrow 0}\left(\frac{\sin 4 x}{\sin 2 x}\right)=1$ and $\quad \lim _{x \rightarrow 0}\left(\frac{\tan x}{x}\right)=1$
(C) $\lim _{x \rightarrow 0}\left(\frac{\sin 4 x}{\sin 2 x}\right)=\infty$ and $\lim _{x \rightarrow 0}\left(\frac{\tan x}{x}\right)=1$
(D) $\lim _{x \rightarrow 0}\left(\frac{\sin 4 x}{\sin 2 x}\right)=2$ and $\quad \lim _{x \rightarrow 0}\left(\frac{\tan x}{x}\right)=\infty$

Question ID - 156936 | SaraNextGen Top Answer

Which one of the following is correct?
(A) $\lim _{x \rightarrow 0}\left(\frac{\sin 4 x}{\sin 2 x}\right)=2$ and $\quad \lim _{x \rightarrow 0}\left(\frac{\tan x}{x}\right)=1$
(B) $\lim _{x \rightarrow 0}\left(\frac{\sin 4 x}{\sin 2 x}\right)=1$ and $\quad \lim _{x \rightarrow 0}\left(\frac{\tan x}{x}\right)=1$
(C) $\lim _{x \rightarrow 0}\left(\frac{\sin 4 x}{\sin 2 x}\right)=\infty$ and $\lim _{x \rightarrow 0}\left(\frac{\tan x}{x}\right)=1$
(D) $\lim _{x \rightarrow 0}\left(\frac{\sin 4 x}{\sin 2 x}\right)=2$ and $\quad \lim _{x \rightarrow 0}\left(\frac{\tan x}{x}\right)=\infty$