SaraNextGen.Com

Sedimentation basin in a water treatment plant is designed for a flow rate of $0.2 \mathrm{~m}^{3} / \mathrm{s}$. The basin is rectangular with a length of $32 \mathrm{~m},$ width of $8 \mathrm{~m},$ and depth of $4 \mathrm{~m}$. Assume that the settling velocity of these particles is governed by the Stokes' law. Given: density of the particles $=2.5 \mathrm{~g} / \mathrm{cm}^{3} ;$ density of water $=1 \mathrm{~g} / \mathrm{cm}^{3} ;$ dynamic viscosity of water $=0.01 \mathrm{~g} /(\mathrm{cm} . \mathrm{s})$ gravitational acceleration $=980 \mathrm{~cm} / \mathrm{s}^{2}$. If the incoming water contains particles of diameter $25 \mu m$ (spherical and uniform), the removal efficiency of these particles is
(A) $51 \%$
(B) $65 \%$
(C) $78 \%$
(D) $100 \%$



Question ID - 157003 | SaraNextGen Top Answer

Sedimentation basin in a water treatment plant is designed for a flow rate of $0.2 \mathrm{~m}^{3} / \mathrm{s}$. The basin is rectangular with a length of $32 \mathrm{~m},$ width of $8 \mathrm{~m},$ and depth of $4 \mathrm{~m}$. Assume that the settling velocity of these particles is governed by the Stokes' law. Given: density of the particles $=2.5 \mathrm{~g} / \mathrm{cm}^{3} ;$ density of water $=1 \mathrm{~g} / \mathrm{cm}^{3} ;$ dynamic viscosity of water $=0.01 \mathrm{~g} /(\mathrm{cm} . \mathrm{s})$ gravitational acceleration $=980 \mathrm{~cm} / \mathrm{s}^{2}$. If the incoming water contains particles of diameter $25 \mu m$ (spherical and uniform), the removal efficiency of these particles is
(A) $51 \%$
(B) $65 \%$
(C) $78 \%$
(D) $100 \%$

1 Answer
127 votes
Answer Key / Explanation : (B) -

$65 \%$

127 votes


127