Euclidean norm (length) of the vector $\left[\begin{array}{lll}4 & -2 & -6\end{array}\right]^{T}$ is
(A) $\sqrt{12}$
(B) $\sqrt{24}$
(C) $\sqrt{48}$
(D) $\sqrt{56}$

Question ID - 157035 | SaraNextGen Top Answer

Euclidean norm (length) of the vector $\left[\begin{array}{lll}4 & -2 & -6\end{array}\right]^{T}$ is
(A) $\sqrt{12}$
(B) $\sqrt{24}$
(C) $\sqrt{48}$
(D) $\sqrt{56}$