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Euclidean norm (length) of the vector $\left[\begin{array}{lll}4 & -2 & -6\end{array}\right]^{T}$ is
(A) $\sqrt{12}$
(B) $\sqrt{24}$
(C) $\sqrt{48}$
(D) $\sqrt{56}$


Question ID - 157035 | Toppr Answer

Euclidean norm (length) of the vector $\left[\begin{array}{lll}4 & -2 & -6\end{array}\right]^{T}$ is
(A) $\sqrt{12}$
(B) $\sqrt{24}$
(C) $\sqrt{48}$
(D) $\sqrt{56}$

1 Answer - 5876 Votes

3537

Answer Key : (D) -

$\sqrt{56}$



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