For the Ordinary Differential Equation $\frac{d^{2} x}{d t^{2}}-5 \frac{d x}{d t}+6 x=0$, with initial conditions $x(0)=0$ and $\frac{d x}{d t}(0)=10,$ the solution is
(A) $-5 e^{2 t}+6 e^{3 t}$
(B) $5 e^{2 t}+6 e^{3 t}$
(C) $-10 e^{2 t}+10 e^{3 t}$
(D) $10 e^{2 t}+10 e^{3 t}$

Question ID - 157125 | SaraNextGen Top Answer

 For the Ordinary Differential Equation $\frac{d^{2} x}{d t^{2}}-5 \frac{d x}{d t}+6 x=0$, with initial conditions $x(0)=0$ and $\frac{d x}{d t}(0)=10,$ the solution is
(A) $-5 e^{2 t}+6 e^{3 t}$
(B) $5 e^{2 t}+6 e^{3 t}$
(C) $-10 e^{2 t}+10 e^{3 t}$
(D) $10 e^{2 t}+10 e^{3 t}$