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A cultivator with a working width of $1.2 \mathrm{~m}$ utilizes $95 \%$ of its width due to overlapping while operating at a forward speed of $2 \mathrm{~km} \mathrm{~h}^{-1} .$ If the time lost in turning and other interruptions is 50 minutes per hectare, the field efficiency of the cultivator in percent is
(A) 79.84
(B) 83.34
(C) 86.97
(D) 90.20



Question ID - 157239 | SaraNextGen Top Answer

A cultivator with a working width of $1.2 \mathrm{~m}$ utilizes $95 \%$ of its width due to overlapping while operating at a forward speed of $2 \mathrm{~km} \mathrm{~h}^{-1} .$ If the time lost in turning and other interruptions is 50 minutes per hectare, the field efficiency of the cultivator in percent is
(A) 79.84
(B) 83.34
(C) 86.97
(D) 90.20

1 Answer
127 votes
Answer Key / Explanation : (A) -

(A) 79.84

127 votes


127