SaraNextGen.Com


For an initial spore load equal to 25 spores per container inoculated with Clostridium botulinum having $\mathrm{D}_{121}=0.25 \mathrm{~min}$, the spoilage probability of the container subjected to $\mathrm{F}_{121}=1.5 \mathrm{~min}$ is
(A) $10^{-5}$
(B) $10^{-6}$
(C) $10^{-8}$
(D) $10^{-9}$


Question ID - 157288 | Toppr Answer

For an initial spore load equal to 25 spores per container inoculated with Clostridium botulinum having $\mathrm{D}_{121}=0.25 \mathrm{~min}$, the spoilage probability of the container subjected to $\mathrm{F}_{121}=1.5 \mathrm{~min}$ is
(A) $10^{-5}$
(B) $10^{-6}$
(C) $10^{-8}$
(D) $10^{-9}$

1 Answer - 5876 Votes

3537

Answer Key : (B) -

(B) $10^{-6}$



SaraNextGen