The Fourier series to represent $x-x^{2}$ for $-\pi \leq x \leq \pi$ is given by $x-x^{2}=\frac{a_{0}}{2}+\sum_{n=1} a_{n} \cos n x+\sum_{n=1} b_{n} \sin n x$ The value of $a_{0}$ (round off to two decimal places), is

Question ID - 157423 | SaraNextGen Top Answer

The Fourier series to represent $x-x^{2}$ for $-\pi \leq x \leq \pi$ is given by $x-x^{2}=\frac{a_{0}}{2}+\sum_{n=1} a_{n} \cos n x+\sum_{n=1} b_{n} \sin n x$ The value of $a_{0}$ (round off to two decimal places), is