A solid disc of radius $r$ rolls without slipping on a horizontal floor with angular velocity $\omega$ and angular acceleration $\alpha$. The magnitude of the acceleration of the point of contact on the disc is
(A) zero
(B) $r \alpha$
(C) $\sqrt{(r \alpha)^{2}+\left(r \omega^{2}\right)^{2}}$
(D) $r \omega^{2}$

Question ID - 157448 | SaraNextGen Top Answer

A solid disc of radius $r$ rolls without slipping on a horizontal floor with angular velocity $\omega$ and angular acceleration $\alpha$. The magnitude of the acceleration of the point of contact on the disc is
(A) zero
(B) $r \alpha$
(C) $\sqrt{(r \alpha)^{2}+\left(r \omega^{2}\right)^{2}}$
(D) $r \omega^{2}$