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Consider two infinitely long thin concentric tubes of circular cross section as shown in the figure. If $D_{1}$ and $D_{2}$ are the diameters of the inner and outer tubes respectively, then the view factor $F_{22}$ is given by


(A) $\left(\frac{D_{2}}{D_{1}}\right)-1$
(B) zero
(C) $\left(\frac{D_{1}}{D_{2}}\right)$
(D)$1-\left(\frac{D_{1}}{D_{2}}\right)$



Question ID - 157468 | SaraNextGen Top Answer

Consider two infinitely long thin concentric tubes of circular cross section as shown in the figure. If $D_{1}$ and $D_{2}$ are the diameters of the inner and outer tubes respectively, then the view factor $F_{22}$ is given by


(A) $\left(\frac{D_{2}}{D_{1}}\right)-1$
(B) zero
(C) $\left(\frac{D_{1}}{D_{2}}\right)$
(D)$1-\left(\frac{D_{1}}{D_{2}}\right)$

1 Answer
127 votes
Answer Key / Explanation : (D) -

$1-\left(\frac{D_{1}}{D_{2}}\right)$

127 votes


127