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Question ID - 48808 | SaraNextGen Top Answer

Consider a  chessboard. Then match the following columns

Column-I

Column- II

(A)

Number of rectangles

(p)

(B)

Number of squares

(q)

441

(C)

Number of ways three squares can be selected if they are not in same row or column

(r)

91

(D)

In how many ways eleven ‘+’ sign can be arranged in the squares if no row remains empty

(s)

2400

CODES :

 

A

B

C

D

 

 

a)

r

s

p

q

 

 

b)

q

r

s

p

 

 

c)

p

q

r

s

 

 

d)

s

p

q

r

 

 

Verified Solutions by SaraNextGen


1 Answer
127 votes
Answer Key / Explanation : (b) -

 

(b)

1. Number of rectangles is equal to number of ways we can select two vertical lines and two horizontal lines. Total number of ways is

If the square is of 1 sq. units like , then we have such  squares.

If the square is of 4 sq. units like shaded region of the squares , then we have such 5 squares in the belt formed by rows 1 and 2. Similarly we have 4 more belts  and 56. Hence, there are  such squares.

Similarly we have  squares of increasing sizes

Hence, total number of squares is

The first square can be selected in 36 ways. If one such square  is selected, we are left with 25 squares; second square cannot be selected from row 1 and column . If second square is , we are left with 16 squares, from which third square can be selected, e.g.,

Hence, number of ways of selections is . But in this one-by-one type of selection order of selection is also consider. Hence, actual number of ways is

d. Given number of ways is equivalent to selecting 11 squares form 36 squares if no row remains empty

Suppose  be the number of squares selected from the  and  row

Then we must have  (where )

The number of positive integral solutions of the above equation is


127 votes

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