Out of a square if side 8 cm, a triangle is drawn with base as one side of the square and third vertex at any point on the opposite side of the square. What is the area of the remaining portion of the square if the triangle is taken out? (a) 16 sq. cm (b) 32 sq. cm (c) 64 sq. cm (d) Cannot be determined

Question ID - 50075 :- Out of a square if side 8 cm, a triangle is drawn with base as one side of the square and third vertex at any point on the opposite side of the square. What is the area of the remaining portion of the square if the triangle is taken out? (a) 16 sq. cm (b) 32 sq. cm (c) 64 sq. cm (d) Cannot be determined

3537

Base = 8 cm, height = 8 cm.

Area of =

Area of the square =

Difference = 32 cm2.

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 Consider the given figure. If the areas of the triangles LDC, BMC, AMC are denoted by x, y, z then (a) x=y=z (b) x=2y=2z (c) y= 2x=2z (d) z = 2x= 2y