SaraNextGen Study App [2022-23]
Last Updated On 23-10-2022 - By Sara

Two point charges q1 ( ) and q2(−25   are placed on the x-axis at x = 1 m and x = 4 m respectively. The electric field (in V/m) at a point y = 3 m on y-axis is,

 

a.

(−63 ) × 102

b.

(81 -81

c.

(63  × 102

d.

(−81 ×102


Question ID - 50123 :-

Two point charges q1 ( ) and q2(−25   are placed on the x-axis at x = 1 m and x = 4 m respectively. The electric field (in V/m) at a point y = 3 m on y-axis is,

 

a.

(−63 ) × 102

b.

(81 -81

c.

(63  × 102

d.

(−81 ×102

1 Answer
5876 Votes
3537

Answer Key : (c) -

Let  &  are the vaues of electric field due to q1  and q2 Respectively magnitude of

E2 =  

E2=

E2=9×103   V/m

        = 9×103 (    − sinθ2

tanθ2 = 3/4

     = 9×103  

Magnitude of  =  

=(9

=9 102

    =9 102 [cos 1( )+sin 1 ]

∴  tan =3       

E1=9 102

E1=9 102 = 102

= 1+ 2 =(63 −27 ) 102 V/m

∴correct answer is (c)



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