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Last Updated On 23-10-2022 - By Sara

The energy required to take a satellite to a height ‘h’ above Earth surface (radius of Earth =6.4×103 km) is E1 and kinetic energy required for the satellite to be in a circular orbit at this height is E2.  Then value of h for which E1 and E2 are equal, is

 a.

1.28×104 km

b.

6.4×103 km

c.

3.2×103 km

d.

1.6×103 km


Question ID - 50139 :-

The energy required to take a satellite to a height ‘h’ above Earth surface (radius of Earth =6.4×103 km) is E1 and kinetic energy required for the satellite to be in a circular orbit at this height is E2.  Then value of h for which E1 and E2 are equal, is

 a.

1.28×104 km

b.

6.4×103 km

c.

3.2×103 km

d.

1.6×103 km

1 Answer
5876 Votes
3537

Answer Key : (c) -

Usurface +E1 =Uh

KE of satellite is zero at earth surface & at height h

E1=

E1=G

E1=

Gravitational attraction FG = mac =

E2

 mv2=

E2 =

E1 =E2

 

= 3200km



Next Question :

If an angle of a triangle remains unchanged but each on its two including sides is doubled, then by what factor does the area get multiplied?

(a)

2

(b)

3

(c)

4

(d)

6


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