# The energy required to take a satellite to a height ‘h’ above Earth surface (radius of Earth =6.4×103 km) is E1 and kinetic energy required for the satellite to be in a circular orbit at this height is E2.  Then value of h for which E1 and E2 are equal, is  a. 1.28×104 km b. 6.4×103 km c. 3.2×103 km d. 1.6×103 km

## Question ID - 50139 :- The energy required to take a satellite to a height ‘h’ above Earth surface (radius of Earth =6.4×103 km) is E1 and kinetic energy required for the satellite to be in a circular orbit at this height is E2.  Then value of h for which E1 and E2 are equal, is  a. 1.28×104 km b. 6.4×103 km c. 3.2×103 km d. 1.6×103 km

3537

Usurface +E1 =Uh

KE of satellite is zero at earth surface & at height h

E1=

E1=G

E1=

Gravitational attraction FG = mac =

E2

mv2=

E2 =

E1 =E2

= 3200km

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