The energy required to take a satellite to a height ‘h’ above Earth surface (radius of Earth =6.4×103 km) is E1 and kinetic energy required for the satellite to be in a circular orbit at this height is E2. Then value of h for which E1 and E2 are equal, is
|
a. |
1.28×104 km |
b. |
6.4×103 km |
|
c. |
3.2×103 km |
d. |
1.6×103 km |
Question ID - 50139 | SaraNextGen Answer The energy required to take a satellite to a height ‘h’ above Earth surface (radius of Earth =6.4×103 km) is E1 and kinetic energy required for the satellite to be in a circular orbit at this height is E2. Then value of h for which E1 and E2 are equal, is
a.
1.28×104 km
b.
6.4×103 km
c.
3.2×103 km
d.
1.6×103 km
The energy required to take a satellite to a height ‘h’ above Earth surface (radius of Earth =6.4×103 km) is E1 and kinetic energy required for the satellite to be in a circular orbit at this height is E2. Then value of h for which E1 and E2 are equal, is
|
a. |
1.28×104 km |
b. |
6.4×103 km |
|
c. |
3.2×103 km |
d. |
1.6×103 km |
Usurface +E1 =Uh
KE of satellite is zero at earth surface & at height h
E1=
E1=G
E1=
Gravitational attraction FG = mac =
E2
mv2=
E2 = 
E1 =E2
= 3200km
