The readings of field book are It is subsequently realised that the distances to D had been interchanged by mistake. The area of the actual filed would be |
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(a) |
1300 sq. m |
(b) |
1500 sq. m |
(c) |
1800 sq. m |
(d) |
2000 sq. m |

The readings of field book are It is subsequently realised that the distances to D had been interchanged by mistake. The area of the actual filed would be |
|||||||

(a) |
1300 sq. m |
(b) |
1500 sq. m |
(c) |
1800 sq. m |
(d) |
2000 sq. m |

1 Answer

127 votes

Interchanging the distances to C and D, the field may be drawn in th adjoining figure.

We have AB = 40, AF = 30, AG = 20, AH = 10, CH = 30, DG = 20, EF = 30.

Area of the field = ar (AHC) + ar(rect. CEFH) + ar (BEF) + ar (BGD) + ar ( AGD)

=

= 1300 m^{2}_{.}

127 votes

127