One diagonal of a parallelogram is 70 cm and the perpendicular distance of this diagonal from either of the outlying vertices is 27 cm. The area of the parallelogram (in sq. m) is |
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(a) |
1800 |
(b) |
1836 |
(c) |
1890 |
(d) |
1980 |

One diagonal of a parallelogram is 70 cm and the perpendicular distance of this diagonal from either of the outlying vertices is 27 cm. The area of the parallelogram (in sq. m) is |
|||||||

(a) |
1800 |
(b) |
1836 |
(c) |
1890 |
(d) |
1980 |

1 Answer

127 votes

Let ABCD be the given gm.

Let AC = 70 cm.

Draw BLAC, DMAC.

Area of gm ACBD = ar (ABC) + ar(ACD) =

= 1890 sq. cm.

127 votes

127