SaraNextGen.Com


A force acts on a 2kg objects so that its position is given as a function of time as X=3t2+5. What is the work done by this force in first 5 seconds?

a.

850J

b.

900J

c.

950J

d.

875J


Question ID - 50176 | SaraNextGen Answer

A force acts on a 2kg objects so that its position is given as a function of time as X=3t2+5. What is the work done by this force in first 5 seconds?

a.

850J

b.

900J

c.

950J

d.

875J

1 Answer - 5876 Votes

3537

Answer Key : (b) -

X=3t2+5

V=

V=6t+0

at   t = 0, v = 0

t=5 sec   v=30m/s

 W.D = KE

W.D=   



SaraNextGen