A force acts on a 2kg objects so that its position is given as a function of time as X=3t2+5. What is the work done by this force in first 5 seconds?
a.
850J
b.
900J
c.
950J
d.
875J
a.
850J
b.
900J
c.
950J
d.
875J
Question ID - 50176 | SaraNextGen Top Answer A force acts on a 2kg objects so that its position is given as a function of time as X=3t2+5. What is the work done by this force in first 5 seconds?
a.
850J
b.
900J
c.
950J
d.
875J
A force acts on a 2kg objects so that its position is given as a function of time as X=3t2+5. What is the work done by this force in first 5 seconds?
|
a. |
850J |
b. |
900J |
|
c. |
950J |
d. |
875J |
1 Answer
127 votes
Answer Key / Explanation : (b) -
X=3t2+5
V=
V=6t+0
at t = 0, v = 0
t=5 sec v=30m/s
W.D = 
KE
W.D=
127 votes
Answer Link
127