In a car race on straight road, car A takes a time t less than car B at the finish and passes finishing point with a speed ’v’ more than that of car B. Both the cars start from rest and travel constant acceleration a1 and a2 respectively. Then ‘v’ is equal to
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Question ID - 50183 | Top Ranker Answer | SaraNextGen In a car race on straight road, car A takes a time t less than car B at the finish and passes finishing point with a speed ’v’ more than that of car B. Both the cars start from rest and travel constant acceleration a1 and a2 respectively. Then ‘v’ is equal to
a.
b.
c.
d.
In a car race on straight road, car A takes a time t less than car B at the finish and passes finishing point with a speed ’v’ more than that of car B. Both the cars start from rest and travel constant acceleration a1 and a2 respectively. Then ‘v’ is equal to
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1 Answer - 5876 Votes
3537
Answer Key : (d) -
Answer LinkFor A & B let time taken by A is t0
From question,
VA−VB−V=(a1−a2)t0−a2t … (i)
XB=Xa=
a1 
a2 
2
=
t0 = 
… (ii)
Putting t0 in equation
V=(a1−a2) 
2t
=
v= 
+
