In a car race on straight road, car A takes a time t less than car B at the finish and passes finishing point with a speed ’v’ more than that of car B. Both the cars start from rest and travel constant acceleration a1 and a2 respectively. Then ‘v’ is equal to
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In a car race on straight road, car A takes a time t less than car B at the finish and passes finishing point with a speed ’v’ more than that of car B. Both the cars start from rest and travel constant acceleration a1 and a2 respectively. Then ‘v’ is equal to
a. |
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b. |
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c. |
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d. |
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For A & B let time taken by A is t0
From question,
VA−VB−V=(a1−a2)t0−a2t … (i)
XB=Xa= a1
a2
2
=
t0 =
… (ii)
Putting t0 in equation
V=(a1−a2) 2t
= v=
+