An unknown metal of mass 192 g heated to a temperature of 100°c was immersed into a brass calorimeter of mass 128 g containing 240 g of water a temperature of 8.4°c calculate the specific heat of the unknown metal if water temperature stabilizes at 21.5°c(specific heat of brass is 394 J k−1 K−1)
(a)
1232 J kg−1 K−1
(b)
458 J kg−1 K−1
(c)
654 J kg−1 K−1
(d)
916 J kg−1 K−1
An unknown metal of mass 192 g heated to a temperature of 100°c was immersed into a brass calorimeter of mass 128 g containing 240 g of water a temperature of 8.4°c calculate the specific heat of the unknown metal if water temperature stabilizes at 21.5°c(specific heat of brass is 394 J k−1 K−1)
(a)
1232 J kg−1 K−1
(b)
458 J kg−1 K−1
(c)
654 J kg−1 K−1
(d)
916 J kg−1 K−1
Question ID - 50251 | SaraNextGen Answer
An unknown metal of mass 192 g heated to a temperature of 100°c was immersed into a brass calorimeter of mass 128 g containing 240 g of water a temperature of 8.4°c calculate the specific heat of the unknown metal if water temperature stabilizes at 21.5°c(specific heat of brass is 394 J k−1 K−1)
(a)
1232 J kg−1 K−1
(b)
458 J kg−1 K−1
(c)
654 J kg−1 K−1
(d)
916 J kg−1 K−1
|
An unknown metal of mass 192 g heated to a temperature of 100°c was immersed into a brass calorimeter of mass 128 g containing 240 g of water a temperature of 8.4°c calculate the specific heat of the unknown metal if water temperature stabilizes at 21.5°c(specific heat of brass is 394 J k−1 K−1) |
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|
(a) |
1232 J kg−1 K−1 |
(b) |
458 J kg−1 K−1 |
|
(c) |
654 J kg−1 K−1 |
(d) |
916 J kg−1 K−1 |
192×S×(100−21.5)
= 128×394×(21.5−8.4)+240×4200×(21.5−8.4)
⇒ S =916
