The electric field of a plane polarized electromagnetic wave in free space at time t=0 is given by an expression (x, y) = 10 cos [(6x+8z)] The magnetic field (x, z, t) is given by :(c is the velocity of light) |
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(a) |
= (6+8)cos [(6x−8z+10ct)] |
(b) |
(6−8)cos[(6x+8z−10ct)] |

(c) |
(6+8)cos[(6x+8z−10ct)] |
(d) |
(6−8)cos[(6x+8z+10ct)] |

The electric field of a plane polarized electromagnetic wave in free space at time t=0 is given by an expression (x, y) = 10 cos [(6x+8z)] The magnetic field (x, z, t) is given by :(c is the velocity of light) |
|||

(a) |
= (6+8)cos [(6x−8z+10ct)] |
(b) |
(6−8)cos[(6x+8z−10ct)] |

(c) |
(6+8)cos[(6x+8z−10ct)] |
(d) |
(6−8)cos[(6x+8z+10ct)] |

1 Answer

5876 Votes

3537

=10 cos [(6+8). (x+z)]

=10 cos []

∴=6+8; direction of waves travel.

i.e. direction of ‘c’.

∴ Direction of will be along

×=

Mag. of will be along ×=

Mag. of ==

∴==

Consider the nuclear fission Ne |
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(a) |
8.3 MeV energy will be released |
(b) |
Energy of 12.4MeV will be Supplied |

(c) |
Energy of 11.9 MeV has to be supplied |
(d) |
Energy of 3.6 MeV will be released |

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