A particle executes simple harmonic motion with an amplitude of 5 cm. When the particle is at 4 cm from the mean position, the magnitude of its velocity in SI units is equal to that of its acceleration. Then, its periodic time in seconds is:
(a)
(b)
(c)
(d)
A particle executes simple harmonic motion with an amplitude of 5 cm. When the particle is at 4 cm from the mean position, the magnitude of its velocity in SI units is equal to that of its acceleration. Then, its periodic time in seconds is:
(a)
(b)
(c)
(d)
Question ID - 50265 | SaraNextGen Answer
A particle executes simple harmonic motion with an amplitude of 5 cm. When the particle is at 4 cm from the mean position, the magnitude of its velocity in SI units is equal to that of its acceleration. Then, its periodic time in seconds is:
(a)
(b)
(c)
(d)
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A particle executes simple harmonic motion with an amplitude of 5 cm. When the particle is at 4 cm from the mean position, the magnitude of its velocity in SI units is equal to that of its acceleration. Then, its periodic time in seconds is: |
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(a) |
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(b) |
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(c) |
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(d) |
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1 Answer - 5876 Votes
3537
Answer Key : (d) -
Answer LinkV=
…(1)
A=−
2x … (2)
|v|=|a| … (3)
=
x
A2−x2=
x2
52−42=
(42)
⇒ 3=
×4
T=2
/
