A particle executes simple harmonic motion with an amplitude of 5 cm. When the particle is at 4 cm from the mean position, the magnitude of its velocity in SI units is equal to that of its acceleration. Then, its periodic time in seconds is:
(a)
(b)
(c)
(d)
A particle executes simple harmonic motion with an amplitude of 5 cm. When the particle is at 4 cm from the mean position, the magnitude of its velocity in SI units is equal to that of its acceleration. Then, its periodic time in seconds is:
(a)
(b)
(c)
(d)
Question ID - 50265 | SaraNextGen Top Answer
A particle executes simple harmonic motion with an amplitude of 5 cm. When the particle is at 4 cm from the mean position, the magnitude of its velocity in SI units is equal to that of its acceleration. Then, its periodic time in seconds is:
(a)
(b)
(c)
(d)
|
A particle executes simple harmonic motion with an amplitude of 5 cm. When the particle is at 4 cm from the mean position, the magnitude of its velocity in SI units is equal to that of its acceleration. Then, its periodic time in seconds is: |
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(a) |
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(b) |
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(c) |
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(d) |
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1 Answer
127 votes
Answer Key / Explanation : (d) -
V=
…(1)
A=−
2x … (2)
|v|=|a| … (3)
=
x
A2−x2=
x2
52−42=
(42)
⇒ 3=
×4
T=2
/
127 votes
Answer Link
127