A metal plate of area 1×10−4m2 is illuminated by a radiation of intensity16 mW/m2. The work function of the metal is 5eV. The energy of the incident photons is 10 eV and only 10% of it produces photo electrons. The number of emitted photo electrons per second and their maximum energy, respectively, will be: [1 eV=1.6×10−19J]
(a)
1010 and 5 eV
(b)
1014 and 10 eV
(c)
1012 and 5 eV
(d)
1011 and 5 eV
A metal plate of area 1×10−4m2 is illuminated by a radiation of intensity16 mW/m2. The work function of the metal is 5eV. The energy of the incident photons is 10 eV and only 10% of it produces photo electrons. The number of emitted photo electrons per second and their maximum energy, respectively, will be: [1 eV=1.6×10−19J]
(a)
1010 and 5 eV
(b)
1014 and 10 eV
(c)
1012 and 5 eV
(d)
1011 and 5 eV
Question ID - 50271 | SaraNextGen Top Answer
A metal plate of area 1×10−4m2 is illuminated by a radiation of intensity16 mW/m2. The work function of the metal is 5eV. The energy of the incident photons is 10 eV and only 10% of it produces photo electrons. The number of emitted photo electrons per second and their maximum energy, respectively, will be: [1 eV=1.6×10−19J]
(a)
1010 and 5 eV
(b)
1014 and 10 eV
(c)
1012 and 5 eV
(d)
1011 and 5 eV
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A metal plate of area 1×10−4m2 is illuminated by a radiation of intensity16 mW/m2. The work function of the metal is 5eV. The energy of the incident photons is 10 eV and only 10% of it produces photo electrons. The number of emitted photo electrons per second and their maximum energy, respectively, will be: [1 eV=1.6×10−19J] |
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(a) |
1010 and 5 eV |
(b) |
1014 and 10 eV |
|
(c) |
1012 and 5 eV |
(d) |
1011 and 5 eV |
=1012