A parallel plate capacitor having capacitance 12 pF is charged by a battery to a potential difference of 10 V between its plates. The charging battery is now disconnected and a porcelain slab of dielectric constant 6.5 is slipped between the plates the work done by the capacitor on the slab is :
(a)
692 pJ
(b)
60 pJ
(c)
508 pJ
(d)
560 pJ
A parallel plate capacitor having capacitance 12 pF is charged by a battery to a potential difference of 10 V between its plates. The charging battery is now disconnected and a porcelain slab of dielectric constant 6.5 is slipped between the plates the work done by the capacitor on the slab is :
(a)
692 pJ
(b)
60 pJ
(c)
508 pJ
(d)
560 pJ
Question ID - 50283 | SaraNextGen Answer
A parallel plate capacitor having capacitance 12 pF is charged by a battery to a potential difference of 10 V between its plates. The charging battery is now disconnected and a porcelain slab of dielectric constant 6.5 is slipped between the plates the work done by the capacitor on the slab is :
(a)
692 pJ
(b)
60 pJ
(c)
508 pJ
(d)
560 pJ
|
A parallel plate capacitor having capacitance 12 pF is charged by a battery to a potential difference of 10 V between its plates. The charging battery is now disconnected and a porcelain slab of dielectric constant 6.5 is slipped between the plates the work done by the capacitor on the slab is : |
|||
|
(a) |
692 pJ |
(b) |
60 pJ |
|
(c) |
508 pJ |
(d) |
560 pJ |
Intial energy of capacitor
=
=
×
=600J
Since battery is disconnected so charge remain same.
Final energy of capacitor
=
=
×
=92
W+
=Ui
W=508 J
