# A parallel plate capacitor having capacitance 12 pF is charged by a battery to a potential difference of 10 V between its plates. The charging battery is now disconnected and a porcelain slab of dielectric constant 6.5 is slipped between the plates the work done by the capacitor on the slab is : (a) 692 pJ (b) 60 pJ (c) 508 pJ (d) 560 pJ

## Question ID - 50283 :- A parallel plate capacitor having capacitance 12 pF is charged by a battery to a potential difference of 10 V between its plates. The charging battery is now disconnected and a porcelain slab of dielectric constant 6.5 is slipped between the plates the work done by the capacitor on the slab is : (a) 692 pJ (b) 60 pJ (c) 508 pJ (d) 560 pJ

3537

Intial energy of capacitor

=

=×=600J

Since battery is disconnected so charge remain same.

Final energy of capacitor

=

=×=92

W+ =Ui

W=508 J

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