SaraNextGen Study App [2022-23]
Last Updated On 23-10-2022 - By Sara

A parallel plate capacitor having capacitance 12 pF is charged by a battery to a potential difference of 10 V between its plates. The charging battery is now disconnected and a porcelain slab of dielectric constant 6.5 is slipped between the plates the work done by the capacitor on the slab is :

(a)

692 pJ

(b)

60 pJ

(c)

508 pJ

(d)

560 pJ


Question ID - 50283 :-

A parallel plate capacitor having capacitance 12 pF is charged by a battery to a potential difference of 10 V between its plates. The charging battery is now disconnected and a porcelain slab of dielectric constant 6.5 is slipped between the plates the work done by the capacitor on the slab is :

(a)

692 pJ

(b)

60 pJ

(c)

508 pJ

(d)

560 pJ

1 Answer
5876 Votes
3537

Answer Key : (c) -

Intial energy of capacitor

= 

=×=600J

Since battery is disconnected so charge remain same.

Final energy of capacitor

 =

=×=92

W+ =Ui

W=508 J



Next Question :

Two kg of a monoatomic gas is at a pressure of 4104 N/m2. The density of the gas is 8kg/m3. What is the order of energy of the gas due to its thermal motion?

(a)

103 J

(b)

105 J

(c)

106 J

(d)

104 J


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