Two identical spherical balls of mass M and radius R each are stuck on two ends of a rod of length 2R and mass M (see figure). The moment of inertia of the system about the axis passing perpendicularly through the centre of the rod is:
(a)
MR2
(b)
MR2
(c)
MR2
(d)
MR2
Two identical spherical balls of mass M and radius R each are stuck on two ends of a rod of length 2R and mass M (see figure). The moment of inertia of the system about the axis passing perpendicularly through the centre of the rod is:
(a)
MR2
(b)
MR2
(c)
MR2
(d)
MR2
Question ID - 50287 | SaraNextGen Answer
Two identical spherical balls of mass M and radius R each are stuck on two ends of a rod of length 2R and mass M (see figure). The moment of inertia of the system about the axis passing perpendicularly through the centre of the rod is:
(a)
MR2
(b)
MR2
(c)
MR2
(d)
MR2
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Two identical spherical balls of mass M and radius R each are stuck on two ends of a rod of length 2R and mass M (see figure). The moment of inertia of the system about the axis passing perpendicularly through the centre of the rod is:
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(a) |
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(b) |
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(c) |
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(d) |
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1 Answer - 5876 Votes
3537
Answer Key : (c) -
Answer LinkFor Ball
Using Parallel axis theorem.
Iball =
MR2+M(2R)2
=
MR2
2 Balls so 
MR2
Irod =for rod 
=
Isystem= IBall + Irod
=
MR2+
=
MR2
