An amplitude modulated signal is given by V(t)=10[1+0.3cos(2.2×10 |
|||

(a) |
1785and 1715 |
(b) |
892.5 and 857.5 |

(c) |
89.25 and 85.75 |
(d) |
178.5 and 171.5 |

An amplitude modulated signal is given by V(t)=10[1+0.3cos(2.2×10 |
|||

(a) |
1785and 1715 |
(b) |
892.5 and 857.5 |

(c) |
89.25 and 85.75 |
(d) |
178.5 and 171.5 |

1 Answer

127 votes

V(t)=10+cosAsinB]

=10+[sin(A+B)−sin(A−B)]

=10+[sin(57.2×10^{4}t) −sin(52.8×10^{4}t)]

=57.2×10^{4}=2πf_{1}

F_{1}==9.1×10^{−4}

≈91 KHz

f_{2}=

≈84 KHz

Side band frequency are

f_{1}=f_{c }−f_{w}=≈85.00 KHz

f_{2}=f_{c}+f_{w}=≈90.00 KHz

127 votes

127