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If the de-Broglie wavelength of an electron is equal to 10−3 times the wavelength of a photon of frequency 6×1014 Hz, then the speed of electron is equal to : (Speed of light =3 ×108 m/s Planck’s constant=6.63×10−34 J.s Mass of electron =9.1×10−31 kg)

(a)

1.45× m/s

(b)

1.7×106 m/s

(c)

1.8×106 m/s

(d)

1.1 ×106 m/s


Question ID - 50303 | SaraNextGen Answer

If the de-Broglie wavelength of an electron is equal to 10−3 times the wavelength of a photon of frequency 6×1014 Hz, then the speed of electron is equal to : (Speed of light =3 ×108 m/s Planck’s constant=6.63×10−34 J.s Mass of electron =9.1×10−31 kg)

(a)

1.45× m/s

(b)

1.7×106 m/s

(c)

1.8×106 m/s

(d)

1.1 ×106 m/s

1 Answer - 5876 Votes

3537

Answer Key : (a) -

=10-3

v=

v=1.45×106 m/s



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