In the figure shown below, the charge on the left plate of the 10 
capacitor is −30
? The Charge on the right plate of the 6 
capacitor is
(a)
−18 μC
(b)
−12 μC
(c)
+12μC
(d)
+18 μF
In the figure shown below, the charge on the left plate of the 10 capacitor is −30? The Charge on the right plate of the 6 capacitor is
(a)
−18 μC
(b)
−12 μC
(c)
+12μC
(d)
+18 μF
Question ID - 50309 | SaraNextGen Top Answer
In the figure shown below, the charge on the left plate of the 10 capacitor is −30? The Charge on the right plate of the 6 capacitor is
(a)
−18 μC
(b)
−12 μC
(c)
+12μC
(d)
+18 μF
|
In the figure shown below, the charge on the left plate of the 10
|
|||
|
(a) |
−18 μC |
(b) |
−12 μC |
|
(c) |
+12μC |
(d) |
+18 μF |
1 Answer
127 votes
Answer Key / Explanation : (d) -
6μF& 4μF are in parallel & total charge on this combination is 30 μC
∴ Charge on 6μF capacitor=
=18 μC
Since charge is asked on right plate therefore is +18 μC
Correct answer is (d)
127 votes
Answer Link
127