The vertices of a family of triangles have integer coordinates. If two of the vertices of all the triangles are (0, 0) and (6, 8), then the least value of areas of the triangles is |
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a) |
1 |
b) |
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c) |
2 |
d) |
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The vertices of a family of triangles have integer coordinates. If two of the vertices of all the triangles are (0, 0) and (6, 8), then the least value of areas of the triangles is |
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a) |
1 |
b) |
|
c) |
2 |
d) |
|
(a)
Let the third vertex be
Area of
As are integers, so we take
(0, 0), (1, 1), (1, 2)
At , it is not possible
At
At
Here, we see that minimum area is 1