Last Updated On 01-06-2023 - By Jeesha Sara
A pendulum is executing simple harmonic motion and its maximum kinetic energy is K1. If the length of the pendulum is doubled and it performs simple harmonic motion with the same amplitude as in the first case, its maximum kinetic energy is K2. Then :
|
a. |
K2 = |
b. |
K2 = |
|
c. |
K2 = 2K1 |
d. |
K2 = K1 |
Question ID - 50365 :- A pendulum is executing simple harmonic motion and its maximum kinetic energy is K1. If the length of the pendulum is doubled and it performs simple harmonic motion with the same amplitude as in the first case, its maximum kinetic energy is K2. Then :
a.
K2 =
b.
K2 =
c.
K2 = 2K1
d.
K2 = K1
A pendulum is executing simple harmonic motion and its maximum kinetic energy is K1. If the length of the pendulum is doubled and it performs simple harmonic motion with the same amplitude as in the first case, its maximum kinetic energy is K2. Then :
|
a. |
K2 = |
b. |
K2 = |
|
c. |
K2 = 2K1 |
d. |
K2 = K1 |
Maximum kinetic energy at lowest point B is given by
K = mg
(1 − cos 
)
where 
= angular amp.
K1 = mg
(1 − cos 
)
K2 = mg(2
)(1 − cos 
)
K2 = 2K1.
Next Question :
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At a distance 12 metres from the foot |
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a) |
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b) |
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c) |
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d) |
None of these |
of a tower 
of height 5 metres, a flagstaff 
on top of 
and the tower subtend the same angle. The, the height of flagstaff is
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