A pendulum is executing simple harmonic motion and its maximum kinetic energy is K_{1}. If the length of the pendulum is doubled and it performs simple harmonic motion with the same amplitude as in the first case, its maximum kinetic energy is K_{2}. Then :

a. |
K |
b. |
K |

c. |
K |
d. |
K |

A pendulum is executing simple harmonic motion and its maximum kinetic energy is K_{1}. If the length of the pendulum is doubled and it performs simple harmonic motion with the same amplitude as in the first case, its maximum kinetic energy is K_{2}. Then :

a. |
K |
b. |
K |

c. |
K |
d. |
K |

1 Answer

127 votes

Maximum kinetic energy at lowest point B is given by

K = mg (1 − cos )

where = angular amp.

K_{1} = mg(1 − cos )

K_{2} = mg(2)(1 − cos )

K_{2} = 2K_{1}.

127 votes

127