A pendulum is executing simple harmonic motion and its maximum kinetic energy is K1. If the length of the pendulum is doubled and it performs simple harmonic motion with the same amplitude as in the first case, its maximum kinetic energy is K2. Then :
a.
K2 =
b.
K2 =
c.
K2 = 2K1
d.
K2 = K1
a.
K2 =
b.
K2 =
c.
K2 = 2K1
d.
K2 = K1
Question ID - 50365 | SaraNextGen Top Answer A pendulum is executing simple harmonic motion and its maximum kinetic energy is K1. If the length of the pendulum is doubled and it performs simple harmonic motion with the same amplitude as in the first case, its maximum kinetic energy is K2. Then :
a.
K2 =
b.
K2 =
c.
K2 = 2K1
d.
K2 = K1
A pendulum is executing simple harmonic motion and its maximum kinetic energy is K1. If the length of the pendulum is doubled and it performs simple harmonic motion with the same amplitude as in the first case, its maximum kinetic energy is K2. Then :
|
a. |
K2 = |
b. |
K2 = |
|
c. |
K2 = 2K1 |
d. |
K2 = K1 |
1 Answer
127 votes
Answer Key / Explanation : (c) -
Maximum kinetic energy at lowest point B is given by
K = mg
(1 − cos 
)
where 
= angular amp.
K1 = mg
(1 − cos 
)
K2 = mg(2
)(1 − cos 
)
K2 = 2K1.
127 votes
Answer Link
127