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When 100 g of a liquid A at 100°C is added to 50 g of a liquid B at temperature 75°C, the temperature of the mixture becomes 90°C. The temperature of the mixture, if 100 g of liquid A at 100°C is added to 50 g of liquid B at 50°C, will be :

a.

80° C

b.

60°C

c.

70°C

d.

85°C


Question ID - 50384 | SaraNextGen Answer

When 100 g of a liquid A at 100°C is added to 50 g of a liquid B at temperature 75°C, the temperature of the mixture becomes 90°C. The temperature of the mixture, if 100 g of liquid A at 100°C is added to 50 g of liquid B at 50°C, will be :

a.

80° C

b.

60°C

c.

70°C

d.

85°C

1 Answer - 5876 Votes

3537

Answer Key : (a) -

100 × SA × [100 − 90] = 50 × SB × (90 − 75)

2SA = 1.5 SB

SA  =  SB

Now, 100 × SA × [100 − T] = 50 × SB (T − 50)

2 ×  (100 − T ) = ( T − 50 )

300 − 3T = 2T − 100

400 = 5T

T = 80



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