A string is wound around a hollow cylinder of mass 5 kg and radius 0.5 m. If the string is now pulled with a horizontal force of 40 N, and the cylinder is rolling without slipping on a horizontal surface (see figure), then the angular acceleration of the cylinder will be (Neglect the mass and thickness of the string) :-

a. |
12 rad/s |
b. |
16 rad/s |

c. |
10 rad/s |
d. |
20 rad/s |

A string is wound around a hollow cylinder of mass 5 kg and radius 0.5 m. If the string is now pulled with a horizontal force of 40 N, and the cylinder is rolling without slipping on a horizontal surface (see figure), then the angular acceleration of the cylinder will be (Neglect the mass and thickness of the string) :-

a. |
12 rad/s |
b. |
16 rad/s |

c. |
10 rad/s |
d. |
20 rad/s |

1 Answer - 5876 Votes

3537

40 + f = m(R) … (i)

40 × R − f × R = mR^{2}

40 − f = mR … (ii)

From (i) and (ii)

= 16