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ABCD is rectangle and E and F are the mid-points of AD and DC. Then the ratio of the areas of EDC and AEFC would be

(a)

1:2

(b)

1:3

(c)

1:4

(d)

2:3



Question ID - 50477 | SaraNextGen Top Answer

ABCD is rectangle and E and F are the mid-points of AD and DC. Then the ratio of the areas of EDC and AEFC would be

(a)

1:2

(b)

1:3

(c)

1:4

(d)

2:3

1 Answer
127 votes
Answer Key / Explanation : (b) -

Let AD = , DC =

 

Then, AE = ED = , DE = FC = .

 

 

Ar(EDF) =

 

Ar(trap. AEFC) = ar (ADC)  ar(EDF) =

 

 

Req. ratio

127 votes


127