ABCD is rectangle and E and F are the mid-points of AD and DC. Then the ratio of the areas of EDC and AEFC would be |
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(a) |
1:2 |
(b) |
1:3 |
(c) |
1:4 |
(d) |
2:3 |
ABCD is rectangle and E and F are the mid-points of AD and DC. Then the ratio of the areas of EDC and AEFC would be |
|||||||
(a) |
1:2 |
(b) |
1:3 |
(c) |
1:4 |
(d) |
2:3 |
Let AD = , DC =
Then, AE = ED = , DE = FC =
.
Ar(EDF) =
Ar(trap. AEFC) = ar (ADC)
ar(
EDF) =
Req. ratio