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The magnitude of torque on a particle of mass 1kg is 2.5 Nm about the origin. If the force acting on it is 1 N, and the distance of the particle from the origin is 5m, the angle between the force and the position vector is (in radians)

a.

b.

c.

d.



Question ID - 50601 | SaraNextGen Top Answer

The magnitude of torque on a particle of mass 1kg is 2.5 Nm about the origin. If the force acting on it is 1 N, and the distance of the particle from the origin is 5m, the angle between the force and the position vector is (in radians)

a.

b.

c.

d.

1 Answer
127 votes
Answer Key / Explanation : (b) -

2.5 = 1 × 5 sin

sin  = 0.5 =

 =

127 votes


127