Out of three numbers, the first is twice the second and is half of the third. If the average of the three numbers is 56, then the difference of first and third numbers is

(a) 12 (b) 20 (c) 24 (d) 48

Out of three numbers, the first is twice the second and is half of the third. If the average of the three numbers is 56, then the difference of first and third numbers is

(a) 12 (b) 20 (c) 24 (d) 48

1 Answer

127 votes

Let the second number be Then, first number = third number =

Required difference =

127 votes

127