In the given circuit diagram, the currents, I1 =–0.3A, I4 = 0.8 A and I5 = 0.4 A, are flowing as shown. The currents I2, I3 and I6 respectively, are :
(a)
1.1 A, 0.4 A, 0.4 A
(b)
−0.4 A, 0.4 A, 1.1 A
(c)
0.4 A, 1.1 A, 0.4 A
(d)
1.1 A, −0.4 A, 0.4 A
In the given circuit diagram, the currents, I1 =–0.3A, I4 = 0.8 A and I5 = 0.4 A, are flowing as shown. The currents I2, I3 and I6 respectively, are :
(a)
1.1 A, 0.4 A, 0.4 A
(b)
−0.4 A, 0.4 A, 1.1 A
(c)
0.4 A, 1.1 A, 0.4 A
(d)
1.1 A, −0.4 A, 0.4 A
Question ID - 50719 | SaraNextGen Top Answer
In the given circuit diagram, the currents, I1 =–0.3A, I4 = 0.8 A and I5 = 0.4 A, are flowing as shown. The currents I2, I3 and I6 respectively, are :
(a)
1.1 A, 0.4 A, 0.4 A
(b)
−0.4 A, 0.4 A, 1.1 A
(c)
0.4 A, 1.1 A, 0.4 A
(d)
1.1 A, −0.4 A, 0.4 A
|
In the given circuit diagram, the currents, I1 =–0.3A, I4 = 0.8 A and I5 = 0.4 A, are flowing as shown. The currents I2, I3 and I6 respectively, are :
|
|||
|
(a) |
1.1 A, 0.4 A, 0.4 A |
(b) |
−0.4 A, 0.4 A, 1.1 A |
|
(c) |
0.4 A, 1.1 A, 0.4 A |
(d) |
1.1 A, −0.4 A, 0.4 A |
1 Answer
127 votes
Answer Key / Explanation : (a) -
From KCL, I3 = 0.8 − 0.4 = 0.4 A
I2 = 0.4 + 0.4 + 0.3
= 1.1 A
I6 = 0.4A
127 votes
Answer Link
127