A galvanometer, whose resistance is 50 ohm, has 25 divisions in it. When a current of 4 ×10–4 A passes through it, its needle (pointer) deflects by one division. To use this galvanometer as a voltmeter of range 2.5 V, it should be connected to a resistance of:
(a)
6250 ohm
(b)
250 ohm
(c)
200 ohm
(d)
6200 ohm
A galvanometer, whose resistance is 50 ohm, has 25 divisions in it. When a current of 4 ×10–4 A passes through it, its needle (pointer) deflects by one division. To use this galvanometer as a voltmeter of range 2.5 V, it should be connected to a resistance of:
(a)
6250 ohm
(b)
250 ohm
(c)
200 ohm
(d)
6200 ohm
Question ID - 50817 | SaraNextGen Top Answer
A galvanometer, whose resistance is 50 ohm, has 25 divisions in it. When a current of 4 ×10–4 A passes through it, its needle (pointer) deflects by one division. To use this galvanometer as a voltmeter of range 2.5 V, it should be connected to a resistance of:
(a)
6250 ohm
(b)
250 ohm
(c)
200 ohm
(d)
6200 ohm
|
A galvanometer, whose resistance is 50 ohm, has 25 divisions in it. When a current of 4 ×10–4 A passes through it, its needle (pointer) deflects by one division. To use this galvanometer as a voltmeter of range 2.5 V, it should be connected to a resistance of: |
|||
|
(a) |
6250 ohm |
(b) |
250 ohm |
|
(c) |
200 ohm |
(d) |
6200 ohm |
1 Answer
127 votes
Answer Key / Explanation : (c) -
Ig = 4 × 10−4 × 25 = 10−2 A
2.5 = (50 + R) 10−2
R = 200 
127 votes
Answer Link
127