An alpha-particle of mass m suffers 1-dimensional elastic collision with a nucleus at rest of unknown mass. It is scattered directly backwards losing, 64% of its initial kinetic energy. The mass of the nucleus is
(a)
4m
(b)
3.5m
(c)
2m
(d)
1.5m
An alpha-particle of mass m suffers 1-dimensional elastic collision with a nucleus at rest of unknown mass. It is scattered directly backwards losing, 64% of its initial kinetic energy. The mass of the nucleus is
(a)
4m
(b)
3.5m
(c)
2m
(d)
1.5m
Question ID - 50858 | SaraNextGen Top Answer
An alpha-particle of mass m suffers 1-dimensional elastic collision with a nucleus at rest of unknown mass. It is scattered directly backwards losing, 64% of its initial kinetic energy. The mass of the nucleus is
(a)
4m
(b)
3.5m
(c)
2m
(d)
1.5m
|
An alpha-particle of mass m suffers 1-dimensional elastic collision with a nucleus at rest of unknown mass. It is scattered directly backwards losing, 64% of its initial kinetic energy. The mass of the nucleus is |
|||
|
(a) |
4m |
(b) |
3.5m |
|
(c) |
2m |
(d) |
1.5m |
1 Answer
127 votes
Answer Key / Explanation : (a) -
mv0 = mv2 − mv1
m
= 0.36×
m
v1 = 0.6v0
M
= 0.64 ×
m
v2 = 
0
mv0 = 
v0− m
0.6v0
1.6m = 0.8 
4m2 = mM.
127 votes
Answer Link
127