A parallel plate capacitor with plates of area 1 m2 each is at a separation of 0.1 m. If the electric field between the plates is 100 N/C, the magnitude of charge each plate is (Take 
0 =8.85×10−12
)
(a)
7.85 × 10−10 C
(b)
6.85 × 10−10 C
(c)
9.85 × 10−10 C
(d)
8.85 × 10−10 C
A parallel plate capacitor with plates of area 1 m2 each is at a separation of 0.1 m. If the electric field between the plates is 100 N/C, the magnitude of charge each plate is (Take 0 =8.85×10−12 )
(a)
7.85 × 10−10 C
(b)
6.85 × 10−10 C
(c)
9.85 × 10−10 C
(d)
8.85 × 10−10 C
Question ID - 50865 | SaraNextGen Top Answer
A parallel plate capacitor with plates of area 1 m2 each is at a separation of 0.1 m. If the electric field between the plates is 100 N/C, the magnitude of charge each plate is (Take 0 =8.85×10−12 )
(a)
7.85 × 10−10 C
(b)
6.85 × 10−10 C
(c)
9.85 × 10−10 C
(d)
8.85 × 10−10 C
|
A parallel plate capacitor with plates of area 1 m2 each is at a separation of 0.1 m. If the electric field between the plates is 100 N/C, the magnitude of charge each plate is (Take |
|||
|
(a) |
7.85 × 10−10 C |
(b) |
6.85 × 10−10 C |
|
(c) |
9.85 × 10−10 C |
(d) |
8.85 × 10−10 C |
1 Answer
127 votes
Answer Key / Explanation : (d) -
E=
=
Q = A
0
Q = (1)(100)(8.85×10−12)
Q = 8.85 × 10−10C
127 votes
Answer Link
127