A bomb of mass 3.0 kg explodes in air into two pieces of masses 2.0 kg and 1.0 kg .The smaller mass goes at a speed of |
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a) |
1.07 kJ |
b) |
2.14 kJ |
c) |
2.4 kJ |
d) |
4.8 kJ |
A bomb of mass 3.0 kg explodes in air into two pieces of masses 2.0 kg and 1.0 kg .The smaller mass goes at a speed of |
|||||||
a) |
1.07 kJ |
b) |
2.14 kJ |
c) |
2.4 kJ |
d) |
4.8 kJ |
(d)
From law of conservation of momentum, when no external force acts upon a system of two (or more) bodies, then the total momentum of the system remains constant.
Momentum before explosion =momentum after explosion.
since bomb v at rest, its velocity is zero, hence,
Total energy imparted is
=1600+3200=4800J
=4.8kJ