# Column-I Column- II (A) If , then is divisible by the greatest prime number which is greater than (p) 16 (B) Between 4 and 2916 is inserted odd number G.M’s. Then the the G.M. is divisible by greatest odd integer which is less than (q) 10 (C) In a certain progression, four consecutive terms are 40, 30, 24, 20. Then the integral part of the next term of the progression is more than (r) 34 (D) to , where H.C.F. , then is less than (s) 30 CODES :   A B C D     a) R,s p,q r,s p,q,r,s     b) p,q,r,s r,s p,q r,s     c) p,q r,s p,q,r,s r,s     d) r,s p,q,r,s r,s p,q

## Question ID - 51119 :- Column-I Column- II (A) If , then is divisible by the greatest prime number which is greater than (p) 16 (B) Between 4 and 2916 is inserted odd number G.M’s. Then the the G.M. is divisible by greatest odd integer which is less than (q) 10 (C) In a certain progression, four consecutive terms are 40, 30, 24, 20. Then the integral part of the next term of the progression is more than (r) 34 (D) to , where H.C.F. , then is less than (s) 30 CODES :   A B C D     a) R,s p,q r,s p,q,r,s     b) p,q,r,s r,s p,q r,s     c) p,q r,s p,q,r,s r,s     d) r,s p,q,r,s r,s p,q

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 (b) 1.    Hence,   Hence, the greatest prime number by which which is divisible is 41 2.  will be the middle mean of odd means and it will be equidistant from the first and last terms. Hence, will also be in G.P. So,    Hence, the greatest odd number by which is divisible is 27 3. Terms are 40, 30, 24, 20. Now,  and Hence, 1/30, 1/24, 1/20 are in A.P. with common difference . Hence, the next term is 1/20+1/120=7/120. Therefore, the next term of given series is . Hence, the integral part of is 17 4.      and  Column-I Column- II (A) If are in G.P., then are in (p) A.P. (B) If , then are in (q) H.P. (C) If are in A.P.; are in G.P. and are in G.P., then are in (r) G.P. (D) If are in G.P., , then are in (s) None of these CODES : A B C D a) q r p r b) r p q s c) s r p q d) p s r q 