Column-I
Column- II
(A)
If 
, then 
is divisible by the greatest prime number which is greater than
(p)
16
(B)
Between 4 and 2916 is inserted odd number 
G.M’s. Then the 
the G.M. is divisible by greatest odd integer which is less than
(q)
10
(C)
In a certain progression, four consecutive terms are 40, 30, 24, 20. Then the integral part of the next term of the progression is more than
(r)
34
(D)
to 
, where H.C.F. 
, then 
is less than
(s)
30
CODES :
A
B
C
D
a)
R,s
p,q
r,s
p,q,r,s
b)
p,q,r,s
r,s
p,q
r,s
c)
p,q
r,s
p,q,r,s
r,s
d)
r,s
p,q,r,s
r,s
p,q
Column-I
Column- II
(A)
If , then is divisible by the greatest prime number which is greater than
(p)
16
(B)
Between 4 and 2916 is inserted odd number G.M’s. Then the the G.M. is divisible by greatest odd integer which is less than
(q)
10
(C)
In a certain progression, four consecutive terms are 40, 30, 24, 20. Then the integral part of the next term of the progression is more than
(r)
34
(D)
to , where H.C.F. , then is less than
(s)
30
CODES :
A
B
C
D
a)
R,s
p,q
r,s
p,q,r,s
b)
p,q,r,s
r,s
p,q
r,s
c)
p,q
r,s
p,q,r,s
r,s
d)
r,s
p,q,r,s
r,s
p,q
Question ID - 51119 | SaraNextGen Top Answer
Column-I
Column- II
(A)
If , then is divisible by the greatest prime number which is greater than
(p)
16
(B)
Between 4 and 2916 is inserted odd number G.M’s. Then the the G.M. is divisible by greatest odd integer which is less than
(q)
10
(C)
In a certain progression, four consecutive terms are 40, 30, 24, 20. Then the integral part of the next term of the progression is more than
(r)
34
(D)
to , where H.C.F. , then is less than
(s)
30
CODES :
A
B
C
D
a)
R,s
p,q
r,s
p,q,r,s
b)
p,q,r,s
r,s
p,q
r,s
c)
p,q
r,s
p,q,r,s
r,s
d)
r,s
p,q,r,s
r,s
p,q
|
Column-I |
Column- II |
||||||||
|
(A) |
If |
(p) |
16 |
||||||
|
(B) |
Between 4 and 2916 is inserted odd number |
(q) |
10 |
||||||
|
(C) |
In a certain progression, four consecutive terms are 40, 30, 24, 20. Then the integral part of the next term of the progression is more than |
(r) |
34 |
||||||
|
(D) |
|
(s) |
30 |
||||||
|
CODES : |
|||||||||
|
|
A |
B |
C |
D |
|
|
|||
|
a) |
R,s |
p,q |
r,s |
p,q,r,s |
|
|
|||
|
b) |
p,q,r,s |
r,s |
p,q |
r,s |
|
|
|||
|
c) |
p,q |
r,s |
p,q,r,s |
r,s |
|
|
|||
|
d) |
r,s |
p,q,r,s |
r,s |
p,q |
|
|
|||
|
(b) 1.
Hence,
Hence, the greatest prime number by which 2.
Hence, the greatest odd number by which 3. Terms are 40, 30, 24, 20. Now,
and
Hence, 1/30, 1/24, 1/20 are in A.P. with common difference 4.
|
which is divisible is 41
will be the middle mean of 
odd means and it will be equidistant from the first and last terms. Hence,
will also be in G.P. So,
is divisible is 27
. Hence, the next term is 1/20+1/120=7/120. Therefore, the next term of given series is 
. Hence, the integral part of 
is 17
and 
