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Four identical particles of mass M are located at the corners of a square of side ‘a’.   What should be their speed if each of them revolves under the influence of others’ gravitational field in a circular orbit circumscribing the square?                                    

                

(a)

1.41

(b)

1.16

(c)

1.21

(d)

1.35



Question ID - 51155 | SaraNextGen Top Answer

Four identical particles of mass M are located at the corners of a square of side ‘a’.   What should be their speed if each of them revolves under the influence of others’ gravitational field in a circular orbit circumscribing the square?                                    

                

(a)

1.41

(b)

1.16

(c)

1.21

(d)

1.35

1 Answer
127 votes
Answer Key / Explanation : (b) -

r = , F=    +  

                                                 

   =  

⇒ v2 =

⇒ v=   =1.16

127 votes


127