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Ship A is sailing towards north−east with velocity  = 30 + 50  km/hr where  points east and , north.  Ship B is at a distance of 80 km\east and 150 km north of Ship A and is sailing towards west at 10 km/hr. A will be at minimum distance from B in

(a)

2.2 hrs.

(b)

4.2 hrs.

(c)

3.2 hrs

(d)

2.6 hrs.


Question ID - 51160 :-

Ship A is sailing towards north−east with velocity  = 30 + 50  km/hr where  points east and , north.  Ship B is at a distance of 80 km\east and 150 km north of Ship A and is sailing towards west at 10 km/hr. A will be at minimum distance from B in

(a)

2.2 hrs.

(b)

4.2 hrs.

(c)

3.2 hrs

(d)

2.6 hrs.

1 Answer
5876 Votes
3537

Answer Key : (d) -

A=30 +50 km/hr

BA =(80 + 150 )km

B =(−10 )km/hr

BA= B A=−10 −30 =−40 −50

Projection of

(  on BA=

   = =

∴t= = =2.6hrs



Next Question :

For the circuit shown, with R1 = 1.0 , R2 = 2.0 , E1 = 2 V and E2 = E3 = 4 V, the potential difference between the points ‘a’ and ‘b’ is approximately (in V)

                     

(a)

2.7

(b)

3.7

(c)

2.3

(d)

3.3


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