A thermally insulated vessel contains 150 g of water at 0°C. Then the air from the vessel is pumped out adiabatically. A fraction of water turns into ice and the rest evaporates at 0°C itself. The mass of evaporated water will be closest to (Latent heat of vaporization of water = 2.10
106 J kg−1 and Latent heat of Fusion of water = 3.36105 J kg−1)
(a)
130g
(b)
150g
(c)
20g
(d)
35g
A thermally insulated vessel contains 150 g of water at 0°C. Then the air from the vessel is pumped out adiabatically. A fraction of water turns into ice and the rest evaporates at 0°C itself. The mass of evaporated water will be closest to (Latent heat of vaporization of water = 2.10106 J kg−1 and Latent heat of Fusion of water = 3.36105 J kg−1)
(a)
130g
(b)
150g
(c)
20g
(d)
35g
Question ID - 51167 | SaraNextGen Top Answer
A thermally insulated vessel contains 150 g of water at 0°C. Then the air from the vessel is pumped out adiabatically. A fraction of water turns into ice and the rest evaporates at 0°C itself. The mass of evaporated water will be closest to (Latent heat of vaporization of water = 2.10106 J kg−1 and Latent heat of Fusion of water = 3.36105 J kg−1)
(a)
130g
(b)
150g
(c)
20g
(d)
35g
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A thermally insulated vessel contains 150 g of water at 0°C. Then the air from the vessel is pumped out adiabatically. A fraction of water turns into ice and the rest evaporates at 0°C itself. The mass of evaporated water will be closest to (Latent heat of vaporization of water = 2.10 |
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|
(a) |
130g |
(b) |
150g |
|
(c) |
20g |
(d) |
35g |
Let amount of water evaporated be m gram,
∴ m
Lv = (150−m) Ls
m
540 = (150−m)
80
⇒ m
20g